Q. 214.5( 2 Votes )

# Examine the diffe

Answer :

Given, …(1)

We need to check whether f(x) is continuous and differentiable at x = 0

A function f(x) is said to be continuous at x = c if,

Left hand limit(LHL at x = c) = Right hand limit(RHL at x = c) = f(c).

Mathematically we can represent it as- Where h is a very small number very close to 0 (h0)

And a function is said to be differentiable at x = c if it is continuous there and

Left hand derivative(LHD at x = c) = Right hand derivative(RHD at x = c) = f(c).

Mathematically we can represent it as-  Finally, we can state that for a function to be differentiable at x = c Checking for the continuity:

Now according to above theory-

f(x) is continuous at x = 0 if - LHL = LHL = {using equation 1}

As sin (-1/h) is going to be some finite value from -1 to 1 as h0

LHL = 02 × (finite value) = 0

LHL = 0 …(2)

Similarly,

RHL = RHL = {using equation 1}

As sin (1/h) is going to be some finite value from -1 to 1 as h0

RHL = (0)2(finite value) = 0 …(3)

And, f(0) = 0 {using equation 1} …(4)

From equation 2,3 and 4 we observe that: f(x) is continuous at x = 0. So we will proceed now to check the differentiability.

Checking for the differentiability:

Now according to above theory-

f(x) is differentiable at x = 0 if - LHD = LHD = {using equation 1}

LHD = As sin (1/h) is going to be some finite value from -1 to 1 as h0

LHD = 0×(some finite value) = 0

LHD = 0 …(5)

Now,

RHD = RHD = {using equation 1}

RHD = As sin (1/h) is going to be some finite value from -1 to 1 as h0

RHD = 0×(some finite value) = 0

RHD = 0 …(6)

Clearly from equation 5 and 6,we can conclude that-

(LHD at x=0) = (RHD at x = 0)

f(x) is differentiable at x = 0

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