# Find all points of discontinuity of the function where

Given,

To find: Points discontinuity of function f(t) where t =

As t is not defined at x = 1 as denominator becomes 0,at x = 1.

x = 1 is a point of discontinuity

f(t) =

f(t) =

Clearly f(t) is not going to be defined whenever denominator is 0 and thus will give a point of discontinuity.

Solution of the following equation gives other points of discontinuities.

-2x2 + 5x – 2 = 0

2x2 – 5x + 2 = 0

2x2 – 4x – x + 2 = 0

2x(x – 2) – (x – 2) = 0

(2x – 1)(x – 2) = 0

x = 2 or x = 1/2

Hence,

f(t) is discontinuous at x = 1, x = 2 and x = 1/2

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