Q. 10
In Fig. 5.11, if A. 130°
B. 50°
C. 80°
D. 30°
Answer :
∠APQ = 50°(Given)
⇒ ∠PQR = 50°(Alternate interior angles)
∠PRD = 130°(Given)
∠PRD = (180°- 130°) = 50° (Forms a Linear pair)
Sum of interior angles of a triangle = 180°
∠ QPR = 180°- ∠PQR-∠PRD
∠ QPR = 180°-100°
∠ QPR = 80°
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