Q. 10

In Fig. 5.11, if A. 130°

B. 50°

C. 80°

D. 30°

Answer :

APQ = 50°(Given)


PQR = 50°(Alternate interior angles)


PRD = 130°(Given)


PRD = (180°- 130°) = 50° (Forms a Linear pair)


Sum of interior angles of a triangle = 180°


QPR = 180°- PQR-PRD


QPR = 180°-100°


QPR = 80°

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