The diagonals of a rhombus bisect each other at right angles.
Let the intersecting point be O.
So, we get right angled triangles.
We know that the Pythagoras Theorem states that in a right triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides.
Let us consider ΔAOB.
By Pythagoras Theorem,
AB2 = AO2 + OB2
AB2 = 212 + 202
AB2 = 441 + 400
AB2 = 841
AB = 29cm
The length of each side of the rhombus is 29cm.
Rate this question :