Answer :
Given that ΔABC is the triangle whose sides are AB = c, AC = b, BC = a
And AD is the bisector of ∠A.
We know that altitude bisects the opposite side.
So, let BD = DC = x.
Since AD bisects ∠A,
AC/AB = CD/DB
Substituting the given values,
b/c = CD/(a-CD)
Cross multiplying,
⇒ b( a – CD) = c (CD)
⇒ ba – b(CD) = c (CD)
⇒ ba = CD (b + c)
⇒ CD = ba/ (b + c)
Since CD = BD,
BD = ba/ (b + c)
BD = ba/(b + c) and DC = ba/(b + c)
Rate this question :
How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
view all courses
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation


RELATED QUESTIONS :
In Fig. 4.243, th
RD Sharma - MathematicsIn Fig. 4.246, if
RD Sharma - MathematicsIn Fig. 4.244, if
RD Sharma - MathematicsIf <img wid
RD Sharma - MathematicsIf <img wid
RD Sharma - MathematicsIf in <img
RD Sharma - MathematicsIn a <img w
RD Sharma - MathematicsIf <img wid
RD Sharma - MathematicsIn <img wid
RD Sharma - Mathematics