Answer :

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Given that ΔABC is the triangle whose sides are AB = c, AC = b, BC = a


And AD is the bisector of A.


We know that altitude bisects the opposite side.


So, let BD = DC = x.


Since AD bisects ∠A,


AC/AB = CD/DB


Substituting the given values,


b/c = CD/(a-CD)


Cross multiplying,


b( a – CD) = c (CD)


ba – b(CD) = c (CD)


ba = CD (b + c)


CD = ba/ (b + c)


Since CD = BD,


BD = ba/ (b + c)


BD = ba/(b + c) and DC = ba/(b + c)


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