A man goes 12 m d

From ΔABC, we note that

A is the starting point.

AB = 12m, BC = 35m

CA = distance from starting point = x m

We know that the Pythagoras Theorem states that in a right triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides.

By Pythagoras Theorem,

CA² = AB² + BC²

CA² = 12² + 35²

CA² = 144 + 1225

CA² = 1369

CA = 37m

The man is 37 m far from the starting point.