Q. 95.0( 3 Votes )

ΔABC is an isosce

Answer :


Δ ABC is an isosceles triangle.


Also, AB = AC = 13 cm


Suppose the altitude from A on BC meets BC at D. Therefore, D is the midpoint of BC.


AD = 5 cm


ΔADB and ΔADC are right-angled triangles.


Applying Pythagoras theorem,


AB2 = BD2 + AD2


BD2 = 132 - 52


BD2 = 169 – 25 = 144


BD = 12 cm


So, BC = 2× 12 = 24 cm


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