Answer :
Δ ABC is an isosceles triangle.
Also, AB = AC = 13 cm
Suppose the altitude from A on BC meets BC at D. Therefore, D is the midpoint of BC.
AD = 5 cm
ΔADB and ΔADC are right-angled triangles.
Applying Pythagoras theorem,
AB2 = BD2 + AD2
⇒BD2 = 132 - 52
⇒ BD2 = 169 – 25 = 144
⇒ BD = 12 cm
So, BC = 2× 12 = 24 cm
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