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70°^, 46°, 64°

Let ∠P, ∠Q and ∠R are three angles of triangle PQR.

Now,

∠P + ∠Q = 116° ___________________ (i)

∠P - ∠Q = 24° ___________________ (i)

Adding equation (i) and (ii),

2 ∠P = 140°

⇒ ∠P = 70° ______________________ (iii)

Subtracting equation (i) and (ii),

2 ∠Q = 92°

⇒ ∠Q = 46° _______________________ (iv)

We know that sum of angles of triangle = 180°

∠P + ∠Q + ∠R = 180° [Sum of angles]

⇒ 70° + 46° + ∠R = 180° [From equation (iii) and (iv)]

⇒ ∠R = 64°