Q. 53.7( 6 Votes )

A ladder is placed in such a way that its foot is at a distance of 15 m from a wall and its top reaches a window 20 m above the ground. Find the length of the ladder.

Answer :


Ladder AB and distance from the window BC = 20 m.


AC is the distance of the ladder from the building = 15 m.


From the figure, ΔABC is a right triangle.


In a right angled triangle


(Hypotenuse) 2 = (Base)2 + (Height)2


where hypotenuse is the longest side.


(AB)2 = (AC)2 + (BC)2


AB2 = (20) 2 + (15) 2


AB2 = 400 + 225 = 625


AB = 25 m


Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos
Basic Proportionality TheoremBasic Proportionality TheoremBasic Proportionality Theorem42 mins
A Peep into Pythagoras TheoremA Peep into Pythagoras TheoremA Peep into Pythagoras Theorem43 mins
Predominant Proof of TrianglesPredominant Proof of TrianglesPredominant Proof of Triangles52 mins
NCERT | Strong Your Basics of TrianglesNCERT | Strong Your Basics of TrianglesNCERT | Strong Your Basics of Triangles39 mins
RD Sharma | Imp. Qs  From TrianglesRD Sharma | Imp. Qs  From TrianglesRD Sharma | Imp. Qs From Triangles41 mins
Quiz | Criterion of Similarity of TriangleQuiz | Criterion of Similarity of TriangleQuiz | Criterion of Similarity of Triangle45 mins
How to Ace Maths in NTSE 2020?How to Ace Maths in NTSE 2020?How to Ace Maths in NTSE 2020?36 mins
R.D Sharma | Solve Exercise -4.2 and 4.3R.D Sharma | Solve Exercise -4.2 and 4.3R.D Sharma | Solve Exercise -4.2 and 4.345 mins
R.D Sharma | Solve Exercise-4.5R.D Sharma | Solve Exercise-4.5R.D Sharma | Solve Exercise-4.545 mins
NCERT | Basic Proportionality TheoremNCERT | Basic Proportionality TheoremNCERT | Basic Proportionality Theorem22 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
caricature
view all courses