Q. 53.7( 6 Votes )

# A ladder is placed in such a way that its foot is at a distance of 15 m from a wall and its top reaches a window 20 m above the ground. Find the length of the ladder.

Ladder AB and distance from the window BC = 20 m.

AC is the distance of the ladder from the building = 15 m.

From the figure, ΔABC is a right triangle.

In a right angled triangle

(Hypotenuse) 2 = (Base)2 + (Height)2

where hypotenuse is the longest side.

(AB)2 = (AC)2 + (BC)2

AB2 = (20) 2 + (15) 2

AB2 = 400 + 225 = 625

AB = 25 m

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