Answer :
Ladder AB and distance from the window BC = 20 m.
AC is the distance of the ladder from the building = 15 m.
From the figure, ΔABC is a right triangle.
In a right angled triangle
(Hypotenuse) 2 = (Base)2 + (Height)2
where hypotenuse is the longest side.
(AB)2 = (AC)2 + (BC)2
⇒AB2 = (20) 2 + (15) 2
⇒ AB2 = 400 + 225 = 625
⇒AB = 25 m
Rate this question :
How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
view all courses
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
