Q. 53.7( 6 Votes )

# A ladder is placed in such a way that its foot is at a distance of 15 m from a wall and its top reaches a window 20 m above the ground. Find the length of the ladder.

Answer :

Ladder AB and distance from the window BC = 20 m.

AC is the distance of the ladder from the building = 15 m.

From the figure, ΔABC is a right triangle.

In a right angled triangle

(Hypotenuse) ^{2} = (Base)^{2} + (Height)^{2}

where hypotenuse is the longest side.

(AB)^{2} = (AC)^{2} + (BC)^{2}

⇒AB^{2} = (20) ^{2} + (15) ^{2}

⇒ AB^{2} = 400 + 225 = 625

⇒AB = 25 m

Rate this question :

How useful is this solution?

We strive to provide quality solutions. Please rate us to serve you better.

PREVIOUSA 13-m-long ladder reaches a window of a building 12 m above the ground. Determine the distance of the foot of the ladder from the building.NEXTTwo vertical poles of height 9 m and 14 m stand on a plane ground. If the distance between their feet is 12 m, find the distance between their tops.

Related Videos

Basic Proportionality Theorem42 mins

A Peep into Pythagoras Theorem43 mins

Predominant Proof of Triangles52 mins

NCERT | Strong Your Basics of Triangles39 mins

RD Sharma | Imp. Qs From Triangles41 mins

Quiz | Criterion of Similarity of Triangle45 mins

How to Ace Maths in NTSE 2020?36 mins

R.D Sharma | Solve Exercise -4.2 and 4.345 mins

R.D Sharma | Solve Exercise-4.545 mins

NCERT | Basic Proportionality Theorem22 mins

Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Expertsview all courses

Dedicated counsellor for each student

24X7 Doubt Resolution

Daily Report Card

Detailed Performance Evaluation