Q. 253.7( 13 Votes )
In the given figure, AM
BC and AN is the bisector of
. Find the measure of
.

Answer :
17.5°
Given, AMBC and “AN” is the bisector of
.
Therefore,
=
(
-
)
⇒ =
(65° -30°)
⇒ = 17.5°
Rate this question :






















Prove that the angles opposite to equal sides of a triangle are equal
RS Aggarwal & V Aggarwal - MathematicsIf the sides of a triangle are produced in order, then the sum of the three exterior angles so formed is
RD Sharma - MathematicsIn Δ ABC, if ∠A = 100° AD bisects ∠A and AD⊥BC. Then, ∠B =
RD Sharma - MathematicsD is any point on side AC of a ΔABC with AB = AC. Show that CD < BD.
NCERT Mathematics ExemplarIn a triangle ABC, if AB = AC and AB is produced to D such that BD = BC, find ∠ACD: ∠ADC.
RD Sharma - MathematicsIn Δ ABC, ∠A=50° and BC is produced to a point D. If the bisectors of ∠ABC and ∠ACD meet at E, then ∠E =
RD Sharma - MathematicsCompute the value of x in each of the following figures:
(i)
(ii)
(iii)
(iv)
In Δ PQR, if PQ=QR and L, M and N are the mid-point of the sides PQ, QR and RP respectively. Prove that LN=MN.
RD Sharma - MathematicsIn a right-angled triangle, one of the acute measures 53°. Find the measure of each angle of the triangle.
RS Aggarwal & V Aggarwal - MathematicsProve that the perimeter of a triangle is greater than the sum of its altitudes.
RD Sharma - Mathematics