# <span lang="EN-US

60°

Given, ::= 3:2:1 and AC CD

Let, A = 3a

B = 2a

C = a

In triangle ABC,

A + B + C = 180°[Sum of angles of triangle]

3a + 2a + a = 180°

6a = 180°

a = 30°

Therefore, C = a = 30°

Now,

ACB + ACD + ECD = 180°[Sum of angles of triangle]

30° + 90° + ECD = 180°

ECD = 60°

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