Answer :

60°


Given, ::= 3:2:1 and AC CD


Let, A = 3a


B = 2a


C = a


In triangle ABC,


A + B + C = 180°[Sum of angles of triangle]


3a + 2a + a = 180°


6a = 180°


a = 30°


Therefore, C = a = 30°


Now,


ACB + ACD + ECD = 180°[Sum of angles of triangle]


30° + 90° + ECD = 180°


ECD = 60°


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