Answer :

(a) In right triangle ALC

Using Pythagoras theorem, we have

AC2 = AL2 + LC2

AC2 = AD2 − DL2 + (DL + DC) 2


(b) In right triangle ALD

Using Pythagoras theorem, we have

AL2 = AD2 - LD2

Again, in ΔABL

Using Pythagoras theorem, we have

AB2 = AL2 + LB2

AB2 = AD2 –DL2 + LB2

AB2 = AD2–DL2 + (BD – DL)2


(c) Adding (1) and (2)

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