Answer :

(a) In right triangle ALC


Using Pythagoras theorem, we have


AC2 = AL2 + LC2


AC2 = AD2 − DL2 + (DL + DC) 2




….(1)


(b) In right triangle ALD


Using Pythagoras theorem, we have


AL2 = AD2 - LD2


Again, in ΔABL


Using Pythagoras theorem, we have


AB2 = AL2 + LB2


AB2 = AD2 –DL2 + LB2


AB2 = AD2–DL2 + (BD – DL)2




……(2)


(c) Adding (1) and (2)




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