Q. 204.1( 25 Votes )

An aeroplane leav

Answer :


Let A be the first aeroplane flied due north at a speed of 1000 km/hr and B be the second aeroplane flied due west at a speed of 1200 km/hr


Distance covered by plane A in 1.5 hrs = 1000 × 32 = 1500km


Distance covered by plane B in 1.5 hrs = 1200 × 32 = 1800km


Now, in right triangle ABC


By using Pythagoras theorem, we have


AB2 = BC2 + AC2


AB2 = (1800)2 + (1500)2


AB2 = 3240000 + 2250000


AB2 = 5490000


AB = 300√61 km


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