Q. 193.7( 10 Votes )
In the given figure, AD divides
in the ratio 1:3 and AD=DB. Determine the value of.

Answer :
X=90
Explanation:
∠BAC + ∠CAE = 180°[Because BE is a straight line]
⇒ ∠BAC + 108° = 180°
⇒ ∠BAC = 72°
Now,
AD = DB
=
∠BAD = ( �)72°= 18°
∠DAC = ( �)72°= 54°
In triangle ABC,
∠A + ∠B + ∠C = 180°[Sum of angles of triangle]
⇒ 72° + 18° + x = 180°
⇒ x = 90°
Rate this question :






















Each question consists of two statements, namely, Assertion (A) and Reason (R). Please select the correct answer.
In the given figure, PQ>PR and QS and RS are the bisectors of ∠Q and ∠R respectively. Show that SQ>SR
In, if
-
=42°and
-
=21°, Find
,
and
.
Of the three angles of a triangle, one is twice the smallest and mother one is thrice the smallest. Find the angle.
RS Aggarwal & V Aggarwal - MathematicsOf the three angles of a triangle are equal and the third angle is greater than each one of them by 18°. Find the angle.
RS Aggarwal & V Aggarwal - MathematicsTwo adjacent angles on a straight line are in the ratio 5:4 Find the measure of each one of these angles.
RS Aggarwal & V Aggarwal - MathematicsIn the adjoining figure, AC>AB and AD is the bisector of ∠A. show that ∠ADC>∠ADB.
In the given figure, ABC is a triangle in which:
:
=3:2:1 and AC
CD. Find the measure of
.
In ∆ABC, ∠B=35°,∠C=65° and the bisector of ∠BAC meets BC in X. Arrange AX, BX and CX in descending order.
In ∆ABC, side AB is produced to D such that BD=BC. If ∠B=60° and ∠A=70°, prove that (i) AD>CD and (ii) AD>AC.