# In the given figure, side BC of ABC is produced to D. If =128° and =43°,Find and .

BAC = 85°, ACB = 52°

Given, =128° and =43°

In triangle ABC,

ACB + ACD = 180° [Because BCD is a straight line]

ACB + 128° = 180°

ACB = 52°

ABC + ACB + BAC = 180° [Sum of angles of triangle ABC]

43° + 52° + BAC = 180°

BAC = 85°

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