Q. 154.2( 11 Votes )

In the given figure, side BC of ABC is produced to D. If =128° and =43°,Find and .


Answer :

BAC = 85°, ACB = 52°


Given, =128° and =43°


In triangle ABC,


ACB + ACD = 180° [Because BCD is a straight line]


ACB + 128° = 180°


ACB = 52°


ABC + ACB + BAC = 180° [Sum of angles of triangle ABC]


43° + 52° + BAC = 180°


BAC = 85°


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