In right-angled triangle AED, applying Pythagoras theorem,AB2 = AE2 + BE2⇒ AE2 = AB2 – BE2 ….(i)In right-angled triangle AED, applying Pythagoras theorem,AD2 = AE2 + ED2⇒ AE2 = AD2 – ED2 ….(ii)Therefore,AB2 – BE2 = AD2 – ED2

Q. 153.8( 13 Votes )

In ΔABC, D is the

Class 10th RS Aggarwal - Mathematics Triangles

Answer :

In right-angled triangle AED, applying Pythagoras theorem,

AB² = AE² + BE²

⇒ AE² = AB² – BE² ….(i)

In right-angled triangle AED, applying Pythagoras theorem,

AD² = AE² + ED²

⇒ AE² = AD² – ED² ….(ii)

Therefore,

AB² – BE² = AD² – ED²

Rate this question :

How useful is this solution?

We strive to provide quality solutions. Please rate us to serve you better.

PREVIOUSFind the length o NEXTIn the given figu

Related Videos

Quiz- Test what you Know45 mins

Quiz- Test what you Know Part 245 mins

BPT ke Master Kaise Bane?46 mins

Pythagoras Theorem ki Application46 mins

Similarity - Apply it like a Champ45 mins

Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts

Dedicated counsellor for each student

24X7 Doubt Resolution

Daily Report Card

Detailed Performance Evaluation

view all courses