Answer :
ABCD is a rhombus where AC = 24 cm and BD = 10 cm.
We know that diagonals of a rhombus bisect each other at 90°.
⇒ ∠AOB = 90°, OA = 12 cm and OB = 5 cm
∴ ΔAOB is a right-angled triangle.
Applying Pythagoras theorem,
BA2 = BO2 + AO2
⇒ BA 2 = 52 + 122
⇒ BA2 = 25 + 144 = 169
⇒ BA = AD = CD = BC = 13 cm
∵Sides of a rhombus are equal.
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