Q. 94.7( 25 Votes )

In the given figure, AB||CD. Prove that p+q-r=180


Answer :

Given AB||CD, AEF = P°, EFG = q°, FGD =


Draw a line FH||AB||CD



HFG = FGD = r° [Because HF||CD and alternate angles] ___________ (i)


EFH = EFG - HFG


EFH = q – r ______________________ (i)


AEF + EFH = 180° [Because AB||HF]


AEF + EFH = 180°


p + (q – r) = 180°


p + q – r = 180°Proved.


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