Q. 45.0( 6 Votes )
The areas of two similar triangles are 169 cm2 and 121 cm2 respectively. If the longest side of the larger triangle is 26 cm, find the longest side of the smaller triangle.
Answer :
Let the two triangles be ABC and PQR and their longest sides are BC and QR.
We know that if two triangles are similar then the ratio of their areas is equal to the ratio of the squares of their longest sides.
Rate this question :
Basic Proportionality Theorem42 mins
A Peep into Pythagoras Theorem43 mins
Predominant Proof of Triangles52 mins
NCERT | Strong Your Basics of Triangles39 mins
RD Sharma | Imp. Qs From Triangles41 mins
Quiz | Criterion of Similarity of Triangle45 mins
How to Ace Maths in NTSE 2020?36 mins
R.D Sharma | Solve Exercise -4.2 and 4.345 mins
R.D Sharma | Solve Exercise-4.545 mins
NCERT | Basic Proportionality Theorem22 mins
, ar (
) = 9 cm2, ar (
) = 16 cm2. If BC = 2.1 cm, then the measure of EF is
. such that ar (
) = 4 ar (
). If BC =12 cm, then QR =
If 
and 
are two triangles such that 
, then Area (
): Area (
) =
The areas of two similar triangles are in respectively 9 cm2 and 16 cm2. The ratio of their corresponding sides is
RD Sharma - MathematicsThe areas of two similar triangles 
and 
are 144 cm2 and 81 cm2 respectively. If the longest side of larger A ABC be 36 cm, then. the longest side of the smaller triangle 
is
In Fig. 4.236, 
and AP : PB = 1 : 2. Find 
[CBSE 2008]
RD Sharma - Mathematics
If 
and 
are two triangles such that 
, then write Area (
): Area (
).
