Q. 45.0( 6 Votes )
The areas of two similar triangles are 169 cm2 and 121 cm2 respectively. If the longest side of the larger triangle is 26 cm, find the longest side of the smaller triangle.
Answer :
Let the two triangles be ABC and PQR and their longest sides are BC and QR.
We know that if two triangles are similar then the ratio of their areas is equal to the ratio of the squares of their longest sides.
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, ar (
) = 9 cm2, ar (
) = 16 cm2. If BC = 2.1 cm, then the measure of EF is
. such that ar (
) = 4 ar (
). If BC =12 cm, then QR =
If and
are two triangles such that
, then Area (
): Area (
) =
The areas of two similar triangles are in respectively 9 cm2 and 16 cm2. The ratio of their corresponding sides is
RD Sharma - MathematicsThe areas of two similar triangles and
are 144 cm2 and 81 cm2 respectively. If the longest side of larger A ABC be 36 cm, then. the longest side of the smaller triangle
is
In Fig. 4.236, and AP : PB = 1 : 2. Find
[CBSE 2008]
RD Sharma - Mathematics
If and
are two triangles such that
, then write Area (
): Area (
).