# In the adjoining figure, AB ||CD are cut by a transversal t at E and F respectively. If =5:4, Find measure of each of the remaining marked angles.

=100°, =80°, =100°=80°, =100°, =80°, =100°, =80°

Given AB ||CD are cut by a transversal t at E and F respectively.

And = 5:4

Let 1 = 5a and 2 = 4a

1 + 2 = 180° [Because AB is a straight line]

5a + 4a = 180°

9a = 180°

a = 20°

Therefore, 1 = 5a

1 = 5 × 20° = 100°

2 = 4a

2 = 4 × 20° = 80°

3 = 1 = 100° [Opposite angles]

4 = 2 = 80° [Opposite angles]

5 = 1 = 100° [Crossponding angles]

6 = 4 = 80° [Crossponding angles]

7 = 5 = 100° [Opposite angles]

8 = 6 = 80° [Opposite angles]

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