Q. 24.1( 14 Votes )

In the adjoining figure, AB ||CD are cut by a transversal t at E and F respectively. If =5:4, Find measure of each of the remaining marked angles.


Answer :

=100°, =80°, =100°=80°, =100°, =80°, =100°, =80°


Given AB ||CD are cut by a transversal t at E and F respectively.


And = 5:4


Let 1 = 5a and 2 = 4a


1 + 2 = 180° [Because AB is a straight line]


5a + 4a = 180°


9a = 180°


a = 20°


Therefore, 1 = 5a


1 = 5 × 20° = 100°


2 = 4a


2 = 4 × 20° = 80°


3 = 1 = 100° [Opposite angles]


4 = 2 = 80° [Opposite angles]


5 = 1 = 100° [Crossponding angles]


6 = 4 = 80° [Crossponding angles]


7 = 5 = 100° [Opposite angles]


8 = 6 = 80° [Opposite angles]


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