Answer :

X=60, y=60, z=70, t=70


Given AB||CD and EF||GH


x = 60° [Opposite angles]


y = x = 60°[Alternate angles]


PQS = APR = 110°[Crossponding angles]


PQS = PQR + y = 110°_____________ (i)


For AB straight line,


y + z + PQR = 180°


z + 110° = 180°[From equation (i)]


z = 70°


AB||CD


Therefore,


t = z = 70°[Because alternate angles]


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