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X=60, y=60, z=70, t=70

Given AB||CD and EF||GH

x = 60° [Opposite angles]

y = x = 60°[Alternate angles]

PQS = APR = 110°[Crossponding angles]

PQS = PQR + y = 110°_____________ (i)

For AB straight line,

y + z + PQR = 180°

z + 110° = 180°[From equation (i)]

z = 70°

AB||CD

Therefore,

t = z = 70°[Because alternate angles]

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