# In the given figure, AB||CD. Find the values of x, y and z.

x=105, y=75, z=50

Given AB||CD

Therefore,

AEF = EFG = 75°[Alternate angles]

y = 75°

For CD straight line,

x + y = 180°

x + 75° = 180°

x = 105°

Again,

EGF + 125° = 180°

EGF = 155°

In triangle EFG,

y + z + EGF = 180°

75°+ z + 155°= 180°

z + 130°= 180°

z = 50°

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