Q. 103.6( 11 Votes )
In the given figure, AB||PQ. Find the value of x and y.
Answer :
x=70, y=50
Given AB||PQ
∠GEF + 20° + 75° = 180°[Because EF is a straight line]
⇒ ∠GEF = 180° - 95°
⇒ ∠GEF = 85°________________ (i)
In triangle EFG,
⇒ X + 25° + 85° = 180° [∠GEF = 85°]
⇒ X = 60°
Now,
⇒ ∠BEF + ∠EFQ = 180°[Interior angles on same side of transversal]
⇒ (20° + 85°) + (25° + Y) = 180°
⇒ Y = 180° - 130°
⇒ Y = 50°
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