# In the given figure, AB||PQ. Find the value of x and y.

x=70, y=50

Given AB||PQ

∠GEF + 20° + 75° = 180°[Because EF is a straight line]

∠GEF = 180° - 95°

∠GEF = 85°________________ (i)

In triangle EFG,

X + 25° + 85° = 180° [∠GEF = 85°]

X = 60°

Now,

∠BEF + ∠EFQ = 180°[Interior angles on same side of transversal]

(20° + 85°) + (25° + Y) = 180°

Y = 180° - 130°

Y = 50°

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