Answer :

x=70, y=50


Given AB||PQ


∠GEF + 20° + 75° = 180°[Because EF is a straight line]


∠GEF = 180° - 95°


∠GEF = 85°________________ (i)


In triangle EFG,


X + 25° + 85° = 180° [∠GEF = 85°]


X = 60°


Now,


∠BEF + ∠EFQ = 180°[Interior angles on same side of transversal]


(20° + 85°) + (25° + Y) = 180°


Y = 180° - 130°


Y = 50°

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