Answer :

X=60, Y=48, Z=72


AOB is a straight line


Therefore, XOP + POQ + YOQ = 180°


Given, x: y: z =5: 4: 6


Let XOP = x° = 5a, POQ = y° = 4a, YOQ = z° = 6a


5a + 4a + 6a = 180°


15a = 180°


a = 12°


Therefore,


x = 5a = 5×12° = 60°


y = 4a = 4×12° = 48°


z = 6a = 6×12° = 72°


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