# <span lang="EN-US

X=60, Y=48, Z=72

AOB is a straight line

Therefore, XOP + POQ + YOQ = 180°

Given, x: y: z =5: 4: 6

Let XOP = x° = 5a, POQ = y° = 4a, YOQ = z° = 6a

5a + 4a + 6a = 180°

15a = 180°

a = 12°

Therefore,

x = 5a = 5×12° = 60°

y = 4a = 4×12° = 48°

z = 6a = 6×12° = 72°

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