Q. 24.4( 12 Votes )

In the given figu

Answer :

(i) To find DOC, we can observe the straight line DB.

DOC + COB = 180° [ sum of all angles in a straight line is 180°]


DOC + 115° = 180°


DOC = 180° - 115°


DOC = 65°


(ii) In ∆DOC,


And given that, CDO = 70°, DOC = 65° (from (i))


DOC + DCO + CDO = 180°


65° + DCO + 70° = 180°


DCO + 135° = 180°


DCO = 180° - 135°


DCO = 45°


(iii) We have derived DCO from (ii), DCO = 45°


Thus, OAB = 45° [ OAB = DCO as ∆ODC ∆OBA]


(iv) It’s given that, CDO = 70°


Thus, OBA = 70° [ OBA = CDO as ∆ODC ∆OBA]


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