Q. 143.9( 14 Votes )

In an isosceles Δ

Answer :

To prove: ∆ACP ∆BCQ

Proof:


Given that, ∆ABC is an isosceles triangle. AC = BC


Also, if ∆ABC is an isosceles triangle,


then CAB = CBA …(i)


Subtracting it by 180° from both sides, we get


180° - CAB = 180° - CBA


CAP = CBQ …(ii)


Also, given that AP × BQ = AC × AC


Or


Or [ AC = BC] …(iii)


Recollecting equations (i), (ii) and (iii),


By SAS-similarity criteria, we get


∆ACP ∆BCQ


Hence, proved.


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