Q. 143.9( 14 Votes )

In an isosceles Δ

Answer :

To prove: ∆ACP ∆BCQ


Given that, ∆ABC is an isosceles triangle. AC = BC

Also, if ∆ABC is an isosceles triangle,

then CAB = CBA …(i)

Subtracting it by 180° from both sides, we get

180° - CAB = 180° - CBA

CAP = CBQ …(ii)

Also, given that AP × BQ = AC × AC


Or [ AC = BC] …(iii)

Recollecting equations (i), (ii) and (iii),

By SAS-similarity criteria, we get


Hence, proved.

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