# In the given figure, AB is a mirror; PQ is the incident ray and QR, the reflected ray. If =112°, Find .

34°

Angle of incidence =angle of reflection.

Therefore, PQA = BQR _____________________ (i)

BQR + PQR + PQA = 180°[Because AQB is a straight line]

BQR + 112° + PQA = 180°

BQR + PQA = 180° - 112°

PQA + PQA = 68° [from equation (i)]

2 PQA = 68°

PQA = 34°

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