Q. 134.3( 12 Votes )
In the given figure, AB is a mirror; PQ is the incident ray and QR, the reflected ray. If 
=112°, Find 
.
Answer :
34°
Angle of incidence =angle of reflection.
Therefore, ∠PQA = ∠BQR _____________________ (i)
⇒ ∠BQR + ∠PQR + ∠PQA = 180°[Because AQB is a straight line]
⇒ ∠BQR + 112° + ∠PQA = 180°
⇒ ∠BQR + ∠PQA = 180° - 112°
⇒ ∠PQA + ∠PQA = 68° [from equation (i)]
⇒ 2 ∠PQA = 68°
⇒ ∠PQA = 34°
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