Q. 134.3( 12 Votes )

In the given figure, AB is a mirror; PQ is the incident ray and QR, the reflected ray. If =112°, Find .


Answer :

34°


Angle of incidence =angle of reflection.


Therefore, PQA = BQR _____________________ (i)


BQR + PQR + PQA = 180°[Because AQB is a straight line]


BQR + 112° + PQA = 180°


BQR + PQA = 180° - 112°


PQA + PQA = 68° [from equation (i)]


2 PQA = 68°


PQA = 34°


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