A vertical pole o

We have

Let the two triangles be ∆ABC and ∆PQR.

Given that, AB = 7.5 cm

BC = 5 m = 500 cm

QR = 24 m = 2400 cm

We have to find PQ = x (say).

We need to prove ∆ABC is similar to ∆PQR.

We can observe that,

∠ABC = ∠PQR = 90°

∠ACB = ∠PRQ [∵ the sum castes same angle at all places at the same time]

Thus, by AA-similarity criteria, we can say

∆ABC ∼ ∆PQR

So,

Substitute the given values in this equation,

⇒

⇒ x = 36 cm

Thus, height of the tower is 36 cm.