Let the two triangles be ∆ABC and ∆PQR.
Given that, AB = 7.5 cm
BC = 5 m = 500 cm
QR = 24 m = 2400 cm
We have to find PQ = x (say).
We need to prove ∆ABC is similar to ∆PQR.
We can observe that,
∠ABC = ∠PQR = 90°
∠ACB = ∠PRQ [∵ the sum castes same angle at all places at the same time]
Thus, by AA-similarity criteria, we can say
∆ABC ∼ ∆PQR
Substitute the given values in this equation,
⇒ x = 36 cm
Thus, height of the tower is 36 cm.
Rate this question :