Answer :
There are two triangles here, ∆APQ and ∆ABC. We shall prove these triangles to be similar.
&
⇒
Also, ∠A = ∠A [common angle]
So by AA-similarity criteria,
∆APQ ∼ ∆ABC
Thus,
And we know
⇒ BC = 3×PQ
Hence, proved.
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