Q. 54.2( 27 Votes )

# M is a point on t

Answer :

(i). Given: ABCD is a parallelogram.

To Prove: Proof: In ∆DMC and ∆NMB,

DMC = NMB [ they are vertically opposite angles]

DCM = NBM [ they are alternate angles]

CDM = MNB [ they are alternate angles]

By AAA-similarity, we can say

∆DMC ∆NMB

So, from similarity of the triangle, we can say Hence, proved.

(ii). Given: ABCD is a parallelogram.

To Prove: Proof: As we have already derived Add 1 on both sides of the equation, we get   [ ABCD is a parallelogram and a parallelogram’s opposite sides are always equal DC = AB] Hence, proved.

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