Q. 54.2( 27 Votes )

M is a point on t

Answer :

(i). Given: ABCD is a parallelogram.

To Prove:


Proof: In ∆DMC and ∆NMB,


DMC = NMB [ they are vertically opposite angles]


DCM = NBM [ they are alternate angles]


CDM = MNB [ they are alternate angles]


By AAA-similarity, we can say


∆DMC ∆NMB


So, from similarity of the triangle, we can say



Hence, proved.


(ii). Given: ABCD is a parallelogram.


To Prove:


Proof: As we have already derived



Add 1 on both sides of the equation, we get




[ ABCD is a parallelogram and a parallelogram’s opposite sides are always equal DC = AB]



Hence, proved.


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