Q. 5

# Find the supplement of each of the following angles.

(i) 63°

(ii) 138°

(iii) of a right angle

(iv) 75°36’

(v) 124°20’40’’

(vi) 108°48’32’’

Answer :

(i) 117°

Supplement of angle = 180° – θ

Supplement of 58° = 180° - 63°

= 117°

(ii) 42°

Supplement of angle = 180° – θ

Supplement of 58° = 180° - 138°

= 42°

(iii) 126°

Right angle = 90°

of a right angle = × 90°

= 54°

Supplement of 54° = 180° - 54°

= 126°

(iv) 104°24’

Supplement of angle = 180° – θ

Supplement of 75°36’ = 180° - 75°36’

= 179°60’ - 75°36’

= 104°24’

(v) 55°39’20’’

Supplement of angle = 180° – θ

Supplement of 124°20’40’ = 180° - 124°20’40’’

= 179°59’60” - 124°20’40’’

= 55°39’20’’

(vi) 71°11’28’’

Supplement of angle = 180° – θ

Supplement of 108°48’32’’ = 180° - 108°48’32’’

= 179°59’60” - 108°48’32’’

= 71°11’28’’

Rate this question :

Two complementary angles are in the ratio 4:5 Find the angles.

RS Aggarwal & V Aggarwal - MathematicsFind the angle which is five times its supplement.

RS Aggarwal & V Aggarwal - MathematicsIn ∆ABC, AB=AC and the bisectors of ∠B and ∠C meet at a point O. prove that BO=CO and the ray AO is the bisector of ∠A.

RS Aggarwal & V Aggarwal - Mathematics

ABC is a triangle in which AB=AC. If the bisectors of ∠B and ∠C meet AC and AB in D and E respectively, prove that BD=CE.

RS Aggarwal & V Aggarwal - Mathematics

In Figure, BA ⊥ AC, DE ⊥ DF such that BA = DE and BF = EC. Show that ΔABC ≅ΔDEF.

NCERT Mathematics Exemplar

Find the angle whose complement is four times its supplement.

RS Aggarwal & V Aggarwal - MathematicsTwo supplementary angles are in the ratio 3:2 Find the angles.

RS Aggarwal & V Aggarwal - MathematicsIn two congruent triangles *ABC* and *DEF*, if *AB* = *DE* and *BC* = *EF*. Name the pairs of equal angles.