# Two supplementary angles are in the ratio 3:2 Find the angles.

108°, 72°

Let angle = X

Supplementary of X = 180° – X

According to question,

X : 180° – X = 3 : 2

X / (180° – X) = 3 / 2

2X = 3(180° – X)

2X = 540° – 3X

2X + 3X = 54

5X = 54

X = 108°

Therefore angle = 108°

And its supplement = 180° – 108° = 72°

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