Q. 113.8( 13 Votes )

# Find the angle whose supplement is four times its complement.

Answer :

60°

Let the angle = X

Complement of X = 90° – X

Supplement of X = 180° – X

According to question,

⇒ 180° – X = 4(90° – X)

⇒ 180° – X = 360° – 4X

⇒ – X + 4X = 360° – 180°

⇒ 3X = 180°

⇒ X = 60°

Therefore angle = 60°

Rate this question :

Two complementary angles are in the ratio 4:5 Find the angles.

RS Aggarwal & V Aggarwal - MathematicsFind the angle which is five times its supplement.

RS Aggarwal & V Aggarwal - MathematicsIn ∆ABC, AB=AC and the bisectors of ∠B and ∠C meet at a point O. prove that BO=CO and the ray AO is the bisector of ∠A.

RS Aggarwal & V Aggarwal - Mathematics

ABC is a triangle in which AB=AC. If the bisectors of ∠B and ∠C meet AC and AB in D and E respectively, prove that BD=CE.

RS Aggarwal & V Aggarwal - Mathematics

In Figure, BA ⊥ AC, DE ⊥ DF such that BA = DE and BF = EC. Show that ΔABC ≅ΔDEF.

NCERT Mathematics Exemplar

Find the angle whose complement is four times its supplement.

RS Aggarwal & V Aggarwal - MathematicsTwo supplementary angles are in the ratio 3:2 Find the angles.

RS Aggarwal & V Aggarwal - MathematicsIn two congruent triangles *ABC* and *DEF*, if *AB* = *DE* and *BC* = *EF*. Name the pairs of equal angles.