The given system of equations is:
x + y + z = 1
2x + 3y + 2z = 2
ax + ay + 2az = 4
The given system of equations can be written in the form of AX = B, where
Now |A| = 1(6a-2a)-1(4a-2a) +1(2a-3a) = a ≠ 0
∴ A is a non-singular matrix and hence A-1 exists.
So the system of equations will be consistent.
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