Q. 134.4( 23 Votes )

Solve system of l

Answer :

The given system of equations is:

2x + 3y + 3z = 5


x – 2y + z = -4


3x - y - 2z = 3


The given system of equations can be written in the form of AX = B, where



Now |A| = 2(4+1)-3(-5) +3(5) = 40 ≠ 0


A is a non-singular matrix and hence A-1 exists.


Now A11 = 5, A12 = 5, A13 = 5, A21 = 3, A22 = -13, A23 = 11, A31 = 9, A32 = 1, A33 = -7


So AdjA =



And hence X = A-1B


So


Hence x = 1, y = 2 and z = -1


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