# The linear equati

(i)

°C

(ii)

350×9 = 5f – 160

5f = 3150 + 160

f = 662°F

(iii) If the temperature is 0°C, then the temperature in Fahrenheit will be-

5f = 160

f = 32°F

And if the temperature is 0°F, then the temperature in Celsius will be-

C = – 17.778

(iv) Since, both are equal, let C = f

9f = 5f – 160

4f = – 160

f = – 40°F

the numerical value of the temperature which is same in both the scale is – 40

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