Q. 44.4( 198 Votes )

Is the following

Answer :

Let the age of one friend be x years.


Age of the other friend will be (20 − x) years.


4 years ago,


age of 1st friend = (x − 4) years


And, age of 2nd friend = (20 − x − 4) = (16 − x) years


Given that,


(x − 4) (16 − x) = 48

16x − 64 − x2 + 4x = 48

x2 − 20x + 112 = 0


Comparing this equation with ax2 + bx + c = 0, we obtain


a = 1, b = −20, c = 112


Discriminant = b2 − 4ac = (− 20)2 − 4 (1) (112) = 400 − 448 = −48


As b2 − 4ac < 0,

Therefore, no real root is possible for this equation and hence, this situation is not possible.

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