Q. 313.5( 2 Votes )

Prove the following identities

tan2 φ – sin2 φ – tan2 φ . sin2 φ = 0

Answer :

Taking LHS = tan2 φ – sin2 φ – tan2 φ sin2 φ




[ cos2 φ + sin2 φ = 1]



= 0


=RHS


Hence Proved


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