Q. 313.5( 2 Votes )

# Prove the following identities

tan^{2} φ – sin^{2} φ – tan^{2} φ . sin^{2} φ = 0

Answer :

Taking LHS = tan^{2} φ – sin^{2} φ – tan^{2} φ sin^{2} φ

[∵ cos^{2} φ + sin^{2} φ = 1]

= 0

=RHS

Hence Proved

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