# Prove the followings identities:(1 + cos θ)(1 – cos θ) = sin2θ

Taking LHS =(1 – cosθ)(1+ cosθ)

Using identity , (a + b) (a – b) = (a2 – b2) , we get

= (1)2 – (cosθ)2

= 1 – cos2 θ

= sin2 θ [ cos2 θ + sin2 θ = 1]

= RHS

Hence Proved

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