Q. 9 B5.0( 4 Votes )

Show that sin(50° + θ) – cos (40° – θ) = 0.

Answer :

LHS = sin (50° + θ) – cos (40° - θ)

We know that,


Sin A = cos (90° - A)


Here, A = 50° + θ


cos {90° -( 50° + θ)} cos (40° - θ)


cos (40° - θ) – cos (40° - θ)


= 0 = RHS


Hence Proved


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