Q. 33.9( 131 Votes )

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Answer :

The parts of the given question are solved below:

(a) We have to solve the given equation for p.

Therefore,

We have,

4= 5(p – 2)

Multiply 5 with both terms on RHS,

4 = 5 p - 10

Add 10 on the both sides of equation

4 + 10 = 5p -10 + 10

14 = 5p

p =

(b) We have to solve the given equation for p.

Therefore,

We have,

- 4 = 5(p – 2)

Multiply 5 with both terms on RHS,

- 4 = 5 p - 10

Add 10 on the both sides of equation

- 4 + 10 = 5p -10 + 10

6 = 5p

Dividing both sides by 5 we get,

p =

(c) We have to solve the given equation for t.

Therefore,

We have,

16 = 4 + 3(t + 2)

16 – 4 = 3(t + 2)

12 = 3(t + 2)

Dividing both sides by 3, we get,



4 = t + 2

Subtract 2 on both sides

4 - 2 = t + 2 - 2

t = 2

(d)We have to solve the given equation for p.

Therefore,

We have,

4 + 5(p - 1) = 34

4 + 5(p - 1) = 34

5(p – 1) = 34 – 4

5(p – 1) = 30

Dividing both sides by 5, we get,

p = 6 + 1

p = 7

(e) We have to solve the given equation for m

Therefore,

We have,

0 = 16 + 4(m - 6)

-16 = 4(m - 6)

Dividing both sides by 4, we get,

-4 = m - 6

- 4 + 6 = m

m = 2

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