# Prove that :sin θ .cos (90° - θ) + cos θ sin (90° - θ).

Taking LHS = sin θ cos (90° - θ) + cos θ sin (90° - θ)

sin θ × sin θ + cos θ × cos θ [ Sin θ = cos (90° - θ) and cos θ = sin (90° - θ) ]

cos2 θ + sin2 θ [ cos2 θ + sin2 θ = 1]

= 1 = RHS

Hence Proved

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