Q. 205.0( 1 Vote )

Prove that :

cos 27+ sin51o = sin63o+cos 39o

Answer :

Taking LHS = cos 27+ sin51o

We know that


cos θ = sin (90° - θ)


Here, θ = 27°


sin (90° - 27°)+ sin 51°


sin 63°+ sin 51°


We also know that


Sin θ = cos (90° - θ)


Here, θ = 51°


sin 63°+ cos (90° - 51°)


sin 63°+ cos 39° = RHS


Hence Proved


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