Q. 25.0( 1 Vote )

# <span lang="EN-US

Given. ABCD is a parallelogram.

AB = CD ; BC = AD

AB = 8.5 cm, AD = 6.5 cm

DAB = 100°

Formula used. Area of parallelogram = base × height

Steps of construction

Step 1 : Draw a line AB of 8.5cm

Step 2 : Make an angle of 100° on point A and extend ray to AD’

Step 3 : Make an arc of 6.5cm on ray AD’ through point A and name the intersection point as D

Step 4 : Draw arc of 6.5cm and 8.5cm from point D and B Respectively

Step 5 : Mark the intersection point as C and join DC and BC

Step 6 : Draw a perpendicular on AB from point C and name the intersection point as E

Area of parallelogram = base × height

= AB × CE

= 8.5cm × 6.4cm

= 54.4cm2

Conclusion. Hence; parallelogram ABCD is constructed and its area

is 54.4cm2

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses
RELATED QUESTIONS :