Q. 1 A4.2( 44 Votes )

# Solve each of the following pairs of equations by reducing them to a pair of linear equation.

Let be p andbe q,

We get the following pair of linear equations:

5p + q = 2 …III

6p – 3q = 1 …IV

Using the elimination method:

Multiplying eq. III by 3 and adding to IV, we get

15p + 3q = 6

6p – 3q = 1

21p = 7

p =

Substitute the value of p in eq. III

But, 3 = x – 1 x = 4

3 = y – 2 y = 5

So, x = 4 and y = 5

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