Q. 12 D5.0( 2 Votes )

If sec 5 θ =cosec (θ -36o), where 5 θ is an acute angle, find the value of θ.

sec 5θ = cosec (θ-36°) …(i)

We know that

sec θ = cosec (90° - θ)

So, Eq. (i) become

Cosec (90° - 5θ) = cosec (θ -36°)

On Equating both the sides, we get

90° - 5θ = θ -36°

-5θ - θ = -36° -90°

-6θ = -126°

θ = 21°

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