Q. 11 B3.7( 3 Votes )

# In a ∆ABC prove that

In ∆ABC,

Sum of angles of a triangle = 180°

A + B + C = 180°

B + C = 180° - A

…(2)

Taking LHS

(from eq (2))

[ tan (90° - θ) = cot θ]

=RHS

Hence Proved

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