Answer :

Given : sin (A+B) =1


Sin(A+B) = sin (90 o) [ sin (90 o)=1]


On equating both the sides, we get


A + B = 90 o …(1)


And


cos(A B) = cos (30 o)


On equating both the sides, we get


A – B = 30 o …(2)


On Adding Eq. (1) and (2), we get


2A = 120 o


A = 60 o


Now, Putting the value of A in Eq.(1), we get


60 o + B =90 o


B = 30 o


Hence, A = 60 o and B = 30 o


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