Q. 8 B4.0( 62 Votes )

# By us

C1 C1 - C2 (i.e. Replacing 1st column by subtraction of 1st and 2nd column)

C2 C2 - C3 (i.e. Replacing 2nd column by subtraction of 2nd and 3rd column) We have a3 - b3 = (a - b)(a2 + ab + b2) and b3 - c3 = (b - c)(b2 + bc + c2)

Therefore taking (a - b) and (b - c) outside the determinant from 1st and 2nd column respectively C1 C1 - C2 (i.e. Replacing 1st column by subtraction of 1st and 2nd column) As a2 - c2) = (a + c)(a - c) therefore taking (a - c) outside the determinant from 1st column we get .

Expanding the determinant along 1st row

LHS = (a - b)(b - c)(a - c)( - (a + b + c))

Adjusting the minus sign with (a - c)

LHS = (a - b)(b - c)(c - a)(a + b + c) = RHS Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation view all courses RELATED QUESTIONS :

Using properties Mathematics - Board Papers

Using properties Mathematics - Board Papers

Using properties Mathematics - Board Papers

Prove the followiMathematics - Board Papers