Answer :

Comparing equation x^{2} — 3√6x + 12 = 0 with ax^{2} + bx + c = 0 we get

a = 1, b = – 3√6 and c = 12

Discriminant (D) = b^{2} – 4ac

⇒ D = (– 3√6)^{2} – 4(1)(12)

⇒ D = (3^{2})(√6)^{2} – 48

⇒ D = 9 × 6 – 48

⇒ D = 54 – 48

⇒ D = 6

D > 0 implies roots are real and distinct and given by

and

and

Therefore x = 2√6 and x = √6

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